Question

2logx+3logy=0 find y in term of x

Answer 1

Explanation:

`{:}\longrightarrow`
`\sf 2log_x+3log_y=0`

`{:}\longrightarrow`
`\sf 3log_y=-2log_x`

`{:}\longrightarrow`
`\sf {\cancel {log}}_y={\frac {2}{3}}{\cancel{log}}_x`

`{:}\longrightarrow`
`\sf y={(2)/(3)}x`

Answer 2

• y = x^(-2/3)

Explanation:

Given

• 2log x + 3log y = 0

Finding y in terms of x

• 3log y = -2log x
• log y = -2/3log x
• log y = log x^(-2/3)
• y = x^(-2/3)