Question

FePO4 + Na2SO4  Fe2(SO4)3 + Na3PO4

If you perform this reaction with 24 grams of FePO4 and an excess Na2SO4, how many grams of Fe2(SO4)3 can you make?

Answer 1

Mass Fe₂(SO₄)₃ : 31.79 g

Further explanation

Reaction

2FePO₄ + 3Na₂SO₄ ⇒ Fe₂(SO₄)₃ + 2Na₃PO₄

mol FePO₄ (MW=150,82 g/mol) :

`\tt (24)/(150.82)=0.159`

mol Fe₂(SO₄)₃ : mol FePO₄ = 1 : 2, so mol Fe₂(SO₄)₃ :

`\tt (1)/(2)* 0.159=0.0795`

mass Fe₂(SO₄)₃ (MW=399,88 g/mol) :

`\tt 0.0795* 399,88 g/mol=31.79~g`