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The roots of 3x^2+kx+12=0 are equal, find k.

2 Answers

2 votes

Answer:

k = 12

Explanation:

3(x² + kx + 2²) = 3(x² + ____x + 4) = 3(x² + 4x + 4) = 3x² + 12x + 12 ⇒ k = 12

answered
User Shinese
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8.1k points
4 votes

Answer:

Explanation:

3x^2+kx+12=0

k= -3x-12/x

answered
User Dave Forgac
by
7.8k points

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