Find the value of :x^2+2xy+y^2-3x-3y-1 have: x^2-y=y^2-x (x\\eqy)

Question

Find the value of :x^2+2xy+y^2-3x-3y-1
have: x^2-y=y^2-x (x
`\\eq`y)

Answer 1

Answer: The answer is x^2+2xy+2y^2–3x–3y–1

Step-by-step explanation: Move 2 to the left of y^2.