Question

A particle of mass 2.5kg is moviy at a steady speed of 12m/s.when it meets with a fixed resistance of 10N.how long does it take to come to rest?​

Answer 1

3s

Step-by-step explanation:

Newtons 2nd Law:

F = m × a

F = force (N)

m = mass (kg)

a = acceleration (m/s²)

-10 = 5/2 × a

a = -4m/s²

12/4 = 3

3s to come to test