Question

You have 16.6 g of water at 40.2 C. How many Joules are needed to warm the water to 44.8 C?

Answer 1

Q = 319.49 J

Step-by-step explanation:

Given that,

Mass, m = 16.6 g

Initial temperature,
`T_i=40.2^(\circ) C`

We need to find the heat needed to warm the water to 44.8 °C. The formula that is used to find the heat required is given by :

`Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\Q=16.6\ g* 4.184\ J/g^(\circ) C* (44.8-40.2)^(\circ) C\\\\Q=319.49\ J`

So, 319.49 J of heat is needed to warm water.