Question

Please solve this exponential equation 3^2x-4(3^x+1)+27=0

Answer 1

3²x-4(3²x+1)+27=0

9x-4(9x+1)+27=0

9x-4×9x-4×1+27=0

9x -36x -4 +27=0

9x-36x= 4-27

-27x= -23

x= -23/-27

x= 23/27