Answer: 0.4920238
Explanation:
Given: z is a standard normal variable.
We know that probability of z lies lies between
two values a and b is given by :-
Pla<2Now, the probability that z lies between -2.41
and O is given by :-
P(-2.41 < 2 < 0) = P(=<0) - P(2< -2.41)
P(-2.41 < 2 < 0) = 0.5 - 0.0079762 = 0.4920238
[By using z-table for standard normal distribution]
Hence, the probability that z lies between -2.41
and 0 = 0.4920238