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4 votes
Find the zeros of f(x) =x^3+2x^2-3x

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User Bsvingen
by
8.8k points

1 Answer

2 votes

Answer: 0, 1, -3

Explanation:

f(x) = x^3 +2x^2 -3x

f(x) = x(x^2 +2x-3)

f(x) = x(x-1)(x+3)

to find zeroes, plug into f(x) and solve for each value of x. doing this gives 0, 1, and -3

answered
User Jachguate
by
8.2k points

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