Question

Question 1

In OC, mAB= 72. Find m/_BCD.
A 72
B 108
C 144
D 180
and maybe 5 & 6 if ur feeling generous

Answer 1

1) Because
`\angle ACB` is a central angle,
`m\angle ACB=72^(\circ)`.

Since
`\angle ACB` and
`\angle BCD` are supplementary, they form a linear pair, and thus
`m\angle BCD=180^(\circ)-72^(\circ)=\boxed{108^(\circ)}`

5) Tangents drawn from an external common point are congruent, so CR=CP=8 and RB=BQ=4. This means that QA=11, and so PA=11 as well. Adding CP+PA, we get AC=19.

6) By the inscribed angle theorem, angle QPR measures 36 degrees.