Question

An equation of the line that passes through (3, 1) and (0, 10).

Answer 1

So the equation of the line that passes through (3, 1) and (0, 10) is y=-3x+10

Explanation:

(3, 1) and (0, 10)

m=y²-y¹/x²-x¹

m=10-1/0-3

m=9/-3

m=-3

y=mx+b

y-y=m(x-x1)

y-1=-3(x-3)

y-1=-3x+9

+1 +1

y=-3x+10