Answer:
a) A´= A 
b) θ₁´ = 29º, θ₂´ = - 169º , θ₃´ = -49º
Step-by-step explanation:
 In this exercise you are asked to give the magnitudes and angles of the vectors from another system of 
reference 
a) The magnitudes 
The magnitude of a vector, the size of which is a scalar, this does not depend on the reference system, since it is obtained by subtracting the coordinates of the end point minus the coordinate of the origin of the vector 
 A = 
- x₀ 
if the vectors are measured in another reference frame 
 x_{f}´ = xx_{f}- U 
 x₀´ = x₀ -U
 
where U is the distance between the two reference frames 
 A´ = x_{f}´ - x₀´ 
we substitute 
 A´ = (x_{f} - U) - (x₀-U) = x_{f} - x₀ 
 A´ = A 
 it does not change
b) Angles 
The given angles are measured from the positive part of the x axis in a counterclockwise direction, it is asked to give these angles from the x axis 
 θ₁ = 29º
 does not change 
 θ₁´ = 29º
 θ₂ = 191º 
 we measure clockwise 
 θ₂´ = θ₂ - 360 
 θ₂´ = 191 - 360 
 θ₂´ = - 169º 
 
 θ₃ =311º 
 we measure clockwise 
 θ₃´ = 311 -360 
 θ₃´ = -49º