Answer:
Complete ionic: 
 .
.
Net ionic: 
 .
. 
Step-by-step explanation:
Start by identifying species that exist as ions. In general, such species include:
- Soluble salts.
- Strong acids and strong bases.
All four species in this particular question are salts. However, only three of them are generally soluble in water: 
 ,
, 
 , and
, and 
 . These three salts will exist as ions:
. These three salts will exist as ions:
- Each 
  formula unit will exist as one formula unit will exist as one
  ion and one ion and one
  ion. ion.
- Each 
  formula unit will exist as one formula unit will exist as one
  ion and two ion and two
  ions (note the subscript in the formula ions (note the subscript in the formula
  .) .)
-  Each 
  formula unit will exist as one formula unit will exist as one
  and two and two
  ions. ions.
 
On the other hand, 
 is generally insoluble in water. This salt will not form ions.
 is generally insoluble in water. This salt will not form ions.
Rewrite the original chemical equation to get the corresponding ionic equation. In this question, rewrite 
 ,
, 
 , and
, and 
 (three soluble salts) as the corresponding ions.
 (three soluble salts) as the corresponding ions. 
Pay attention to the coefficient of each species. For example, indeed each 
 formula unit will exist as only one
 formula unit will exist as only one 
 ion and one
 ion and one 
 ion. However, because the coefficient of
 ion. However, because the coefficient of 
 in the original equation is two,
 in the original equation is two, 
 alone should correspond to two
 alone should correspond to two 
 ions and two
 ions and two 
 ions.
 ions. 
Do not rewrite the salt 
 because it is insoluble.
 because it is insoluble.
 .
.
Eliminate ions that are present on both sides of this ionic equation. In this question, such ions include one unit of 
 and two units of
 and two units of 
 . Doing so will give:
. Doing so will give:
 .
.
Simplify the coefficients:
 .
.