What is the value of k that makes the equation (4x^2y^2+5xy+k)+(kx^2y^2-2xy-6)=7x^2+kxy-3

Question

asked Sep 10, 2021 56.4k views

1 Answer

FFT · Answer 1 · 2021-09-14T08:02:05+0000

Answer:

k=7x^(2)-4x^(2)y^(2)-3xy+3

x^(2)y^(2)-xy

pretend the underline is like the line for a fraction/ division

Explanation: