Question

Solve cos^2 (B) + 3cos(B) + 2 = 0 for
B, 0 < B < 360

Please help

Answer 1

Explanation:

`\cos {}^(2) (b) + 3 \cos(b) + 2 = 0`

`( \cos(b) + 2)( \cos(b) + 1) = 0`

`\cos(b) = - 2`

Cosine have a range of [-1,1] so b is undefined for the first factor

`\cos(b) = - 1`

`b = 180`