Question

How many moles of Gold (III) sulfide must decompose to produce 4.32 moles of gold

metal given the reaction Au2S3 --> 2Au + 35

Answer 1

2.16 moles of Au₂S₃ are decomposed.

Step-by-step explanation:

Given data:

Number of moles of gold (III) sulfide decomposed = ?

Number of moles of gold metal formed = 4.32 mol

Solution:

Chemical equation:

Au₂S₃ → 2Au + 3S

Now we will compare the moles of Au₂S₃ with gold metal.

Au : Au₂S₃

2 : 1

4.32 : 1/2×4.32 = 2.16

2.16 moles of Au₂S₃ are decomposed.