Question

A sample of air at 58.6 kPa is expanded from 250 mL to 655 mL. If thetemperature remains constant, what is the final pressure in kPa?

Answer 1

22.366 kPa

Step-by-step explanation:

The final pressure can be found by using the formula for Boyle's law which is

`P_1V_1 = P_2V_2`

Since we are finding the final pressure

`P_2 = (P_1V_1)/(V_2) \\`

From the question

58.6 kPa = 58600 Pa

We have

`P_2 = (58600 * 250)/(655) = (14650000)/(655) \\ = 22366.4122... \\ = 22366`

We have the final answer as

22.366 kPa

Hope this helps you