Question

A pitched ball is hit by a batter at a 45° angle and just clears the outfield fence, 107 m away. If the fence is at the same height as the pitch, find the velocity of the ball when it left the bat. Ignore air resistance.

Answer 1

31 m/s

Step-by-step explanation:

Answer 2

31 m/s

Step-by-step explanation:

`R=(v^2i sin(20))/(g)`

`98=(v^2i sin(2)*(45)))/(9.80)`

`98=(v^2i sin (90))/(9.80)`

`98=(v^2i)/(9.80)`

`ui=31 m/s`