Question

How many atoms are present in 9.8g of H2SO4​

Answer 1

Step-by-step explanation:

98 gH

2

​

SO

4

​

contains1 mole of H

2

​

SO

4

​

.

1 mole of H

2

​

SO

4

​

contain=1 mole of sulphur atoms.

∴9.8 g of H

2

​

SO

4

​

contain =0.1 mol of sulphur atom.

Thus, number of sulphur-atoms =n×N

A

​

(in 9.8 g of H

2

​

SO

4

​

)

=0.1×6.023×10

23

=0.6023×10

23

.