Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s) + 3Cl₂ (g)→2AlCl3 (s) You are given 31.0 g of aluminum and 36.0 g of chlorine gas. ▼ Part A If you had excess

Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction:

2Al(s) + 3Cl₂ (g)→2AlCl3 (s)
You are given 31.0 g of aluminum and 36.0 g of chlorine gas.
▼
Part A
If you had excess chlorine, how many moles of of aluminum chloride could be produced from 31.0 g of aluminum?
Express your answer to three significant figures and include the appropriate units.

Please help! I cannot solve it!

1 Answer

Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s) + 3Cl₂ (g)→2AlCl3 (s) You are given 31.0 g of aluminum and 36.0 g of chlorine gas.…

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

Related questions

Categories

Other Questions