Question

A force of 1.50 N acts on a 0.20 kg trolley so as to accelerate it along an air track.

The track and force are horizontal and in line. How fast is the trolley going after acceleration from rest through 30 cm, if friction is negligible?

Answer 1

Answer: The trolley is moving at 2.12m/s

Step-by-step explanation:

Given from the question that the track and force are horizontal and inline, we have that

F= ma

where F= force= 1.50 N

m= mass = 0.2kg

therefore Acceleration , a = F/ m= 1.50/0.2 =7.5 m/s^2

To find how fast the trolley is going ie the Velocity, v

Having that

initial velocity at rest , u = 0,

acceleration a = 7.5 and

and distance, s = 30 cm = 30/100 = 0.30 m

we use motion equation that

v² = u² + 2 a s

v² = 0² + 2 x 7.5 x 0.30

v² = 4.5

v =
`√(4.5)`

v = 2.12 m/s