Question

Rewrite the equation by completing the square 3+x=x^2+3x

Answer 1

(x+1)^2 =4

x=-1±2

Explanation:

I got it right on khan

Answer 2

`(x+1)^2=4`

Explanation:

• 
  `3+x=x^2+3x` is our equation
• first, get all the x terms on one side so the equation equals a constant number
• 
  `3+x-(x)=x^2+3x-x\\3=x^2+2x\\x^2+2x=3`
• Then add to both sides the square of half of the coefficient of x : the coefficient of x here is 2 so
• the square of half of 2 is
  `(1)^2` then
• 
  `x^2+2x+(1)^2=3+(1)^2\\x^2+2x+1=4\\`
• If you factor the left side you get
• 
  `x^2+2x+1=4\\(x+1)^2=4`