asked 54.3k views
5 votes
Solve algebraically for all x values

Solve algebraically for all x values-example-1
asked
User Guu
by
8.4k points

2 Answers

6 votes
x= 5
Simplify the equation

x=4=36-12x + X^2
Move the expression to the left
x-4-36+12x-x^2=0
Collect like terms
Calculate
13x-40-x^2=0
Reorder the terms

-x^2+13x-40 = 0
Change the signs
-x^2+13x+40=0
Rewrite the expression
x^2-5x-8×+40=0
Factor the expressions
x•( x-5)-8(x-5 )=0
Factor the expression
(x-5)•(x-8)=0
Separate into possible cases
x-5=0
x-8=0
Solve the equations
x=5
x=8
Check the solutions
6=6
10=6
x=5 is a solution
x=8 is not a solution
answered
User Vaibhav Shah
by
8.6k points
11 votes

Radical Equations

Solve algebraically for all x values

√(x - 4) + x = 6

To solve for x, make sure to remove first the radical sign before simplifying. To remove the radical sign (since it is square root) raise each side of the equation with an exponent of 2.

  • √(x - 4)² + x = 6
  • x - 4 + x = 6

Then start simplifying.

  • x - 4 + x = 6
  • x + x - 4 = 6
  • 2x = 10
  • x = 5

Answer:

  • The value of x is 5.

Wxndy~~

answered
User NEOatNHNG
by
9.7k points

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