Question

What is the equation of the line that is parallel to the line y = x + 4 and passes through the point (6, 5)?

y = x + 3
y = x + 7
y = 3x – 13
y = 3x + 5

Answer 1

L = x - 1

Explanation:

Let the equation of the line we are trying to find be L.

Since L is parallel to y, they would have the same gradient

So: L = x + c

c is the constant or the y-intercept

Sub in the point (6 , 5)

5 = 6 + c

c = -1

∴ L = x - 1