Answer:1) bacteria size = b(initial) * e^(r * t) 
 
initial size = 300 
final size = 1600. 
 
Substituting the values into the main equation: 
 
1600 = 300 * e^(r * 35 - 20) 
solving for 'r'. 
 
1600 = 300 * e^(r * 15) 
 
1600/300 = e^(r * 15) 
taking natural log on both sides to eliminate the power 
 
ln(16/3) = ln[e^(r * 15)] 
 
ln(16/3) = r * 15 
 
r = ln(16/3) / 15 
 = 0.11159843 
 = 11.16% 
 
To find the initial bacteria size, 
Given: t = 20 
 
300 = b * e^(0.1116 * 20) 
 
Solving for b: 
 
300 = b * e^2.232 
 
b = 300/e^2.232 
 
b = 32 
Explanation: