Question

Iron react with oxygen to form Iron (III) Oxide. How many moles of iron (III) Oxide is in 138.5g?

Answer 1

0.87mole

Step-by-step explanation:

The reaction equation is given as;

4Fe + 3O₂ → 2Fe₂O₃

Number of moles of Fe₂O₃ in 138.5g

To solve this problem;

Number of moles =
`(mass)/(molar mass)`

Molar mass of Fe₂O₃ = 2(56) + 3(16) = 160g/mol

Now;

Number of moles =
`(138.5)/(160)` = 0.87mole