Question

what is the equation of the line that passes through (6,2) and is perpendicular to the a line with slope -1/3

Answer 1

`y = - (1)/(3) x + 4`

Explanation:

point slope formula for equation of line

`y - y1 = m(x - x1)`

point is (6,2) slope is -1/3

`y - 2 = - (1)/(3) (x - 6) \\ y - 2 = - (1)/(3) x + 2 \\ y = - (1)/(3) x + 4`