Question

If the volume of a gas is 958 mL at 75.0 C, at what temperature would the volume of the gas decrease to 822 mL

Answer 1

75.0 degrees Celsius = 75.0 + 273 = 348 K.

Assuming pressure is held constant,

`(958)/(348)=(822)/(T_(2)) \\ \\ (348)/(958)=(T_(2))/(822) \\ \\ T_(2)=((822)(348))/(958) \approx 299 \text{ K} \\ \\ T_(2) \approx 299-273=\boxed{26^(\circ) \text{ C}}`