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F(3) = (x + 1)2 – 16 Number of x-intercepts?

F(3) = (x + 1)2 – 16 Number of x-intercepts?
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F(3) = (x + 1)2 – 16
Number of x-intercepts?

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User Graciela
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1 Answer

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y=mx+b

y=2/3 x −14/ 3

Y equals 2 over 3 (x) minus (negative) 14 over 3
answered
User Milind Thakkar
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