Oliver estimates the weight of of his cat to be 16 pounds. The actual weight of the cat is 14.25 pounds. What is the percent error of Oliver's estimate rounded to the neare…

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asked Mar 1, 2021 53.1k views

2 Answers

Manosim · Answer 1 · 2021-03-06T21:06:23+0000

Given:

Estimated weight of a cat = 16 pounds

Actual weight of that cat = 14.25 pounds

To find:

The percent error to the nearest tenth of a percent.

Solution:

We know that,

$\text{Percent error}=\frac{\text{Estimated value - Actual value}}{\text{Actual value}}* 100$

Using the above formula, we get

$\text{Percent error}=(16-14.25)/(14.25)* 100$

$\text{Percent error}=(1.75)/(14.25)* 100$

$\text{Percent error}=0.122807* 100$

$\text{Percent error}=12.2807$

Round the percent error to the nearest tenth of a percent.

$\text{Percent error}\approx 12.3$

Therefore, the percent error is 12.3%.