Answer:
15
Explanation:
Let 2n+1 be the first odd integer.
Therefore, the consecutive odd integers will be 2n+3 and 2n+5
If the sum of the consecutive odd integers is 51 then:
⇒ 2n + 1 + 2n + 3 + 2n + 5 = 51
⇒ 6n + 9 = 51
⇒ 6n = 42
⇒ n = 7
To find the values of the integers, substitute the found value of n into the expressions:
- First integer: 2(7) + 1 = 15
- Second integer: 2(7) + 3 = 17
- Third integer: 2(7) + 5 = 19
Therefore, the three consecutive odd integers that sum to 51 are 15, 17 and 19. The smallest of which is 15.