Question

ELECTRICITY The impedance in one part of a series circuit is 1 + 3j ohms and the impedance in another part of the circuit is 7 - 5j ohms. Add

these complex numbers to find the total impedance in the circuit.
=j ohms

Answer 1

Total impedance in circuit = 8 - 2j ohms

Explanation:

Given:

Circuit one = 1 + 3j ohms

Circuit two = 7 - 5j ohms

Find:

Total impedance in circuit

Computation:

Total impedance in circuit = Circuit one + Circuit two

Total impedance in circuit = 1 + 3j + 7 - 5j

Total impedance in circuit = 8 - 2j ohms