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Find the equation of the circle with center at (3,-2) and radius of 3.

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User Bezalel
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1 Answer

6 votes

Answer:

The equation of the circle is (x - 3)² + (y + 2)² = 9

Explanation:

The form of the equation of a circle is (x - h)² + (y - k)² = r², where

  • h is the x-coordinate center of the circle
  • k is the y-coordinate of the center of the circle
  • r is the radius of the circle

∵ The center of a circle is (3, -2)

x-coordinate of the center is 3

y-coordinate of the center is -2

h = 3 and k = -2

∵ The radius of the circle is 3

r = 3

→ Substitute them in the form of the equation above

∵ (x - 3)² + (y - -2)² = (3)²

∴ (x - 3)² + (y + 2)² = 9

The equation of the circle is (x - 3)² + (y + 2)² = 9

answered
User Pmhargis
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8.2k points

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