Question

Determine f(-2/3) for the function f(x)=3x²+2x+1​

Answer 1

1

Explanation:

To evaluate, substitute x = -
`(2)/(3)` into f(x), that is

f(-
`(2)/(3)` )

= 3(-
`(2)/(3)` )² + 2(-
`(2)/(3)` ) + 1

= 3(
`(4)/(9)` ) -
`(4)/(3)` + 1

=
`(4)/(3)` -
`(4)/(3)` + 1

= 0 + 1

= 1

Answer 2

1

Explanation:

f(x) = 3x² + 2x + 1

f(-2/3) = 3x² + 2x +1

f(-2/3) = 3(-2/3)² + 2(-2/3) + 1

Substitute the value in for all the x's

f(-2/3) = 3(4/9) + 2(-2/3) + 1

f(-2/3) = 12/9 + (-4/3) + 1

f(-2/3) = 4/3 + (-4/3) + 1

Subtracting 4/3 by (-4/3) gets you 0 so I didn't write it down.

f(-2/3) = 1

So, the answer I got is 1