Question

A solution of ammonia has a pH of 11.8. What is the concentration of OH– ions in the solution

Answer 1

`~~~~~\text{pH} + \text{pOH} = 14\\\\\implies \text{pOH} = 14- \text{pH}\\\\\implies \text{pOH} = 14 - 11.8\\\\\implies \text{pOH} = 2.2\\\\\text{Now,}\\\\~~~~~~~\text{pOH}= -\log\left[\text{OH}^(-1)\right]\\\\\implies \left[\text{OH}^(-1) \right] = 10^{-\text{pOH}} = 10^(-2.2)~ = 0.006309~M\\\\\text{Hence the concentration of OG}^(-1)~ \text{is 0.006309~M}`