What is the discriminant of the quadratic equation, 4x^2-8x-5=0

Question

asked Oct 6, 2021 155k views

2 Answers

Malhobayyeb · Answer 1 · 2021-10-11T19:52:16+0000

Answer:

$\Delta=144$

Explanation:

For a quadratic in standard form, the discriminant is given by:

$\Delta=b^2-4ac$

We have the equation:

4x^2-8x-5=0

Hence, our a=4; b=-8; and c=-5.

Substituting into our formula, we acquire:

$\Delta=(-8)^2-4(4)(-5)$

Evaluate:

$\Delta=64+80$

Add:

$\Delta=144$

Therefore, our discriminant is 144.

Notes:

Since our discriminant is a positive value, this tells us that our quadratic has two real roots.