Question

How do you do this question?

Answer 1

y= 4x -5 x^-1

Explanation:

xy'+y=8x

y' + y/x =8

linear DE

integrating factor = e^∫1/x dx = x

y = 1/x ( ∫8x dx +C)

y= 1/x (4x^2 +C)

y= 4x + C x^-1

C is any constant.. in this case -5 is satisfying equation