Question

A 1500 kg car is parked at the top of a hill 5.2 m high. What is the velocity of the car, in meters per second, when it reaches the bottom of the hill?

Answer 1

Step-by-step explanation:

The car will fall with acceleration due to gravity which is equal to 9.8 m /s²

For downward fall ,

initial velocity u = o

acceleration due to gravity = g = 9.8 m /s

final velocity v = ?

displacement h = 5.2 m

v² = u² + 2 gh

v² = 0 + 2 x 9.8 x 5.2

= 101.92

v = 10.1 m /s