Question

In the circle shown, chords AC and BD intersect at E . if AE=8, EC=6, and BE=4. how long is DE?

10

12

14

16

Answer 1

12

Explanation:

Answer 2

`DE = 12`

Explanation:

Given:

AE = 8,

EC = 6,

BE = 4.

Required:

Length of DE

SOLUTION:

According to the Intersecting Chords Theorem,
`DE * BE = AE * EC`

Plug in the values into the equation. We would have:

`DE * 4 = 8 * 6`

`DE * 4 = 48`

Divide both sides by 4

`DE = (48)/(4)`

`DE = 12`