Find three consecutive odd integers such that when the third is subtracted from five times the sum of the first and second, the result is 798 more than the first.

Question

asked May 12, 2021 114k views

1 Answer

Jeshua Lacock · Answer 1 · 2021-05-18T08:10:09+0000

9514 1404 393

Answer:

99, 101, 103

Explanation:

Let x represent the smallest. Then the sum of the first two is (x+x+2) and the third is x+4. The problem statement tells us the relation ...

5(2x +2) -(x +4) = x +798

10x +10 -x -4 = x +798

8x = 792

x = 99

The integers are 99, 101, 103.

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Check

5(99 +101) -103 = 99 +798

897 = 897 . . . . answer checks OK