Question

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6/11
What is the equation of the line that passes through point (4. 12) and has a y-intercept
of - 2?

Answer 1

7x - 2y - 4 = 0

Explanation:

from the perpendicular equation formula,

y/a + x/b = 1

x1 = 4

y1 = 12

a = -2

b= ?

Inserting the values into the above formula,

12/-2 + 4/b = 1

-6 + 4/b = 1

4/b = 7

b = 4/7

putting a and b into the original formula,

y/-2 + x/(4/7) = 1

-y/2 + 7x/4 = 1 (×4)

-2y + 7x = 4

7x - 2y - 4 = 0

Therefore, the equation of the line is;

7x - 2y - 4 = 0