Question

2. Calculate the mass, in grams, for 3.47 moles of each of the following:

a. lead(II) acetate
b. sodium chloride

Answer 1

Step-by-step explanation:

1 moles Lead(II) Acetate to grams = 325.28804 grams

3.47 moles Lead(II) Acetate to grams = 325.28804 ×3.47 grams=1128.749 grams

1 moles sodium chloride to grams=58.5 grams

3.47 moles sodium chloride to grams=58.5×3.47 grams

=202.995 grams