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What is the sqaure root of (x-3/7) divided by 12x+7 divided by 76.3x?

1 Answer

1 vote

Answer:


\sqrt{(3x)/(3) } + (10)/(109) x

Step by step:


\sqrt{x-(3)/(7) =
\sqrt{(49x-21)/(7) }


\sqrt{(49x-21)/(7) } ÷ 12x+7=
\sqrt{(7x-3x)/(12)} + 7


\sqrt{(7x-3x)/(12)} + 7 ÷ 76.3x =
\sqrt{(3x)/(3) } + (10)/(109) x

Hope this helps!

answered
User Mikaelb
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