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The nuclear reaction that powers the sun involves the fusion of four protons (mp = 1.673x10-27 kg) into a helium nucleus (mHe = 6.645x10-27 kg). The process involves several ste…

The nuclear reaction that powers the sun involves the fusion of four protons (mp = 1.673x10-27 kg) into a helium nucleus (mHe = 6.645x10-27 kg). The process involves several ste…
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The nuclear reaction that powers the sun involves the fusion of four protons (mp = 1.673x10-27 kg) into a helium nucleus (mHe = 6.645x10-27 kg). The process involves several steps, but the net reaction is simply: 4p  He + energy. How much energy is released overall in each fusion process? Give your answer in J and MeV

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User Maloneypatr
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Step-by-step explanation:

it's 5 + 5 + 5 + 12 + 5 x 7 x 7 7+ 8 5+6+ +8 +9 + 9 5

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User Frank Andrew
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