Question

In the given figure ab parallel cd find the value of x​

Answer 1

angle efd = 130

180-50=130

angle ahe =23

180-157= 23

draw a imaginary line from h to f

this will create a triangle

now angle hfc = 90

90-50=40

now angle hfe =

90 - 23 = 67

therefore ,

x =

67+40+x=180

107 + x = 180

x = 180-107

x=73

Answer 2

Step-by-step explanation: x = 73°

Draw PQ through E and parallel to AB, CD

Have x = ∠QED + ∠QEB

because PQ // CD => ∠QED = 50°

AB // PQ => ∠QEB + 157° = 180°

=> ∠QEB = 180 - 157 = 23°

=> x = 23° + 50° = 73°

( PQ is in the same direction as AB and CD )