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What is the equation of the line perpendicular to y=-1/5x -2 and contains the point (2, -10)?

asked
User Torina
by
8.7k points

2 Answers

5 votes

Answer:

y = 5x -20

Explanation:

for the line to be perpendicular it must have the inverse slope

therefore m = 5

no substitute the point (2, -10) in for (x, y) respectively to find the y intercept

-10 = 5(2) + b

-10 = 10 + b

b = -20

the equation will be y = 5x -20

answered
User Haseeb Mohamed
by
8.6k points
2 votes

Answer:

y= 5x-20

Explanation:

I didn't understand if I had to find the perpendicular line or parallel haha.

You’re welcome :)

answered
User Dan Polites
by
7.7k points

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