Question

At​ noon, a tank contained 5 cm of water. After several​ hours, it contained 4 cm of water. What is the percent decrease of water in the​ tank?

Answer 1

20%

Explanation:

Given parameters:

Initial volume of water = 5cm³

New volume of water = 4cm³

Unknown:

Percentage decrease of water in the tank = ?

Solution:

To find the percentage decrease;

Percentage decrease =
`(Old - New)/(Old)` x 100

Percentage decrease =
`(5-4)/(5)` x 100 = 20%