Question

What is the vertex of: y = x^2 + 8x - 10

Answer 1

vertex = -4, -26

Explanation:

The standard form of a quadratic function is :
`y=ax^(2) +bx+c`
The function here : y =
`x^(2)` + 8x - 10
is in this form with a=1, b=8 and c = -10
x-coord of vertex =
`(-b)/(2a)`

`x_(vertex) =(-8)/(2) = -4`
To find corresponding value of y-coord of vertex , substitute

x = -4 into the function.
x=-4 :
`y=(-4)^(2) +(8*(-4))-10 = 16 +(-32)-10=-26`