Question

Bird man is flying horizontally at a speed of 30m/a and a height of 69 m. Bird man releases a turd directly above the start of the field. How far from the start of the field should the robot hood the bucket to catch the turd?

Answer 1

The distance is
`d = 112.5 \ m`

Step-by-step explanation:

From the question we are told that

The horizontal speed is
`v_x = 30 \ m/s`

The height is
`s = 69 \ m`

Generally from kinematic equation we have that

`s = ut + (1)/(2) gt^2`

Here u is the initial velocity of the turd in the vertical direction and the value is 0 m/s

So

`69 = 0 * t + (1)/(2) * 9.8 t^2`

=>
`t = \sqrt{(2 * 69)/(4.9) }`

=>
`t = 3.75 \ s`

Generally the distance which the robot have to hood the bucket in order to catch the turd is mathematically represented as

`d = v_x * t`

=>
`d = 30 * 3.75`

=>
`d = 112.5 \ m`