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Given the exponential function
f(x) = -2(0.8)^x, what is the value of f(x) when x =0?

1 Answer

1 vote

Answer: -2

Work Shown:


f(x) = -2(0.8)^x\\\\f(0) = -2(0.8)^0\\\\f(0) = -2(1)\\\\f(0) = -2\\\\

In the third step, I used the idea that
x^0 = 1 where x is any nonzero number.

answered
User Amit Upadhyay
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